Specific Heat Calculator

Online Tutoring Is The Easiest, Most Cost-Effective Way For Students To Get The Help They Need Whenever They Need It.

SIGN UP FOR A FREE TRIAL




Specific Heat Calculator is used to calculate the amount of energy required to raise temperature of unit mass (1 gram) of a pure substance by 1 degree. Specific heat tells us the measure of how thermally insensitive a substance is to the addition of energy.

Q = c m ΔT


Example 1: Find the specific heat of 350 g of a material when 34,700 Joules of heat are applied, and the temperature rises from 22ºC to 173ºC.

For the given problem:

m = mass = 350g

Q = energy = 34700 joules

 ΔT = change in temperature = 173-22 = 151? C

We need to find the c specific heat. Now Since Q = cmΔT, therefore c = Q/mΔT

c = 34700/(350 x 151) = 34700/52850 = 0.65657521286 J/(g x ?C)


Example 2: Find the final temperature of 400 g of a material when 24,000 Joules of heat are applied, and the initial temperature was 20 ?C. The specific heat is 7.5 J/(g?C)

m =mass=400g

Q = energy = 24000 joules

 ΔT = change in temperature = x-20 =(x–20)? C

c = Specific heat =7.5 J/(g?C)

We need to find the final temperature. Now Since Q = cmΔT, therefore ΔT = Q/mc

ΔT =24000/(400x7.5)=80 ?C.

Final temperature x=80+20 = 100?C.



HAVE A QUESTION? Chat With Our Tutoring Experts Now