Specific Heat Calculator

Online Tutoring Is The Easiest, Most Cost-Effective Way For Students To Get The Help They Need Whenever They Need It.

Specific Heat Calculator is used to calculate the amount of energy required to raise temperature of unit mass (1 gram) of a pure substance by 1 degree. Specific heat tells us the measure of how thermally insensitive a substance is to the addition of energy.

Q = c m ΔT

Example 1: Find the specific heat of 350 g of a material when 34,700 Joules of heat are applied, and the temperature rises from 22ºC to 173ºC.

For the given problem:

m = mass = 350g

Q = energy = 34700 joules

ΔT = change in temperature = 173-22 = 151? C

We need to find the c specific heat. Now Since Q = cmΔT, therefore c = Q/mΔT

c = 34700/(350 x 151) = 34700/52850 = 0.65657521286 J/(g x ?C)

Example 2: Find the final temperature of 400 g of a material when 24,000 Joules of heat are applied, and the initial temperature was 20 ?C. The specific heat is 7.5 J/(g?C)

m =mass=400g

Q = energy = 24000 joules

ΔT = change in temperature = x-20 =(x–20)? C

c = Specific heat =7.5 J/(g?C)

We need to find the final temperature. Now Since Q = cmΔT, therefore ΔT = Q/mc

ΔT =24000/(400x7.5)=80 ?C.

Final temperature x=80+20 = 100?C.