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For the given problem: To bring radical on left side we will subtract both sides by 22

√(2x + 5) + 22 - 22 = 30 -22

√(2x + 5) = 8

Then square both the sides, we get

[√(2x + 5)]

2x+5 = 64 ; 2x+5 - 5 = 64 – 5

2x = 59; x = 59/2 = 29.5

For the given problem: To isolate radical we will subtract both sides by √(5x+3)

√(5x+5) = 6 + √(5x+3)

Square both the sides of the equation

[√(5x+5)]2 = [6 + √(5x+3)]

5x+5 = 36 + (5x+3) + 2x6√(5x+3)

5x+5 -36 - (5x+3) = 12√(5x+3)

[– 34]

1156 = 144(5x+3) ; 1156 = 720 x+432

720x= 724

X=1.00