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Q

whose degree of p is more than one of degree of q. if the degree of the numerator is less than the degree of the denominator then the function not having the slant asymptote.

Step 1: Find the degree of the denominator to check the function can have the slant asymptote

=> Degree of the numerator = 2

=> Degree of the denominator = 1

Degree of the numerator is more than one of degree of the denominator. So the given function having the slant asymptote.

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x-3

Solution 2:

Step 1: Find the degree of the denominator to check the function can have the slant asymptote

Degree of the numerator = 2 > Degree of the denominator = 1

So the given function can have the slant asymptote.

Step 2: we can divide the numerator by the denominator using synthetic division