Online Tutoring Is The Easiest, Most Cost-Effective Way For Students To Get The Help They Need Whenever They Need It.
Slant asymptote calculator is used to find the asymptote for any function which is in the form P
Q
whose degree of p is more than one of degree of q. if the degree of the numerator is less than the degree of the denominator then the function not having the slant asymptote.
Solution 1: Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
=> Degree of the numerator = 2
=> Degree of the denominator = 1
Degree of the numerator is more than one of degree of the denominator. So the given function having the slant asymptote.
Step 3: Therefore, the slant asymptote is x + 4.
Example 2: Find the slant asymptote of the function y = x2-5x+6
--------------------
x-3
Solution 2:Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
Degree of the numerator = 2 > Degree of the denominator = 1
So the given function can have the slant asymptote.
Step 2: we can divide the numerator by the denominator using synthetic division
HAVE A QUESTION?
Chat With Our Tutoring Experts Now
I just want you to know how great Brinda has been in tutoring me on probability. She is patient and very knowledgeable in all concepts. I look forward to many more sessions with her. I appreciate her help and the great work that Tutor Pace is doing.
-
9th Grade, from Barbara
Thank you for your excellent tutoring services. It has surely made a lot of difference in our child's academic performance.
-
9th Grader, from Venkat (father of Sai)
I have enjoyed my session with Aparna and it was helpful. I will hope to see her as my Math tutor in future sessions as well.
-
10th Grade, from Senia Revayo
Your tutor has been such an inspiration to me as I have difficulty getting some of the physics concepts down and truly understanding them. She takes the time to fully explain each and every aspect of any problem I might ask for help and always with encouragement and humor.