Slant asymptote calculator is used to find the asymptote for any function which is in the form P
Q
whose degree of p is more than one of degree of q. if the degree of the numerator is less than the degree of the denominator then the function not having the slant asymptote.
Solution 1: Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
=> Degree of the numerator = 2
=> Degree of the denominator = 1
Degree of the numerator is more than one of degree of the denominator. So the given function having the slant asymptote.
Step 3: Therefore, the slant asymptote is x + 4.
Example 2: Find the slant asymptote of the function y = x2-5x+6
--------------------
x-3
Solution 2: Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
Degree of the numerator = 2 > Degree of the denominator = 1
So the given function can have the slant asymptote.
Step 2: we can divide the numerator by the denominator using synthetic division
Q
whose degree of p is more than one of degree of q. if the degree of the numerator is less than the degree of the denominator then the function not having the slant asymptote.
Solution 1: Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
=> Degree of the numerator = 2
=> Degree of the denominator = 1
Degree of the numerator is more than one of degree of the denominator. So the given function having the slant asymptote.
Step 3: Therefore, the slant asymptote is x + 4.
Example 2: Find the slant asymptote of the function y = x2-5x+6
--------------------
x-3
Solution 2: Steps for solving the slant asymptotes are as follow :-
Step 1: Find the degree of the denominator to check the function can have the slant asymptote
Degree of the numerator = 2 > Degree of the denominator = 1
So the given function can have the slant asymptote.
Step 2: we can divide the numerator by the denominator using synthetic division
