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Filename: controllers/calculator.php

Line Number: 37

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Now we write the fraction with one of the factors as the denominator and A and B as unknown numerator. A/x

+ B/x+1So when we add these fractions with the simplified result we get,

3x+2/x(x+1) = A/x + B/x+1; 3x+2=A(x+1)+B(x)

3(x)+2(1)=(A+B)x+A(1); 3=A+B; 2=A; A=2 and B=1

Answer: 2/x +1/(x+1)

Now we know that the denominator is x(x-1)

x

x

Let x=1 à 1+1 = 0+0+C+0=C, C= 2; Let x=0 à 1=0+0+0–D, D=-1

Let x=-1; 1+1=-4A+2B+6; 2A–B=2; Let x=2 à 4+1=2A+2B+3; 1=A+B

Answer : A=1, C=2, D=-1

1/(x-1) + 2/(x-1)