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Given function: f(x) = x + 2

In order to find the coordinate points, we can first give random values for ‘x’.

Let x = 0, then f(0) = 0+ 2 = 2 > (x, y)= (0, 2)

Let x = -1, then f(-1) = -1+ 2 = 1 > (x, y)= (-1, 1)

Let x = 1, then f(1) = 1+ 2 = 3 > (x, y)= (1, 3)

Hence > (0, 2), (-1, 1), (1, 3) are few coordinate points for the given function.

Given function: f(x) = 2x+ 1

In order to find the coordinate points, we can first give random values for ‘x’.

Let x = 0, then f(0) = 2(0)+ 1 = 1 > (x, y)= (0, 1)

Let x = -1, then f(-1) = 2(-1)+ 1 = -1 > (x, y)= (-1, -1)

Let x = 1, then f(1) = 2(1)+ 1= 3 > (x, y)= (1, 3)

Hence > (0, 1), (-1, -1), (1, 3) are 3 coordinate points for the given function.